
Alexander W. answered 09/18/20
Biology & Ecology for Middle School, High School, and College
AA=350
Aa=100
aa=150
p^2 +2pq +q^2
p=?
q=?
p= A allele frequency
q= a allele frequency
p allele frequency is (AA + (1/2)Aa ) / total number of alleles
so p = (350 + 100 / 2 ) / 600 = 400 / 600= 0.66 =p
We can either do the same thing to solve for q (a allele frequency) or we can just know that p + q =1 since the allele frequencies always have to add up to 100%. Once you know either p or q you can find the other allele freq.
0.66 + q = 1
q = 0.44
So the allele frequencies are
A = 0.66
a = 0.44
and to find the genotype frequencies, it's just each genotypes dived by the total number of alleles.
Homogeneous AA 350/600 = 0.58
Heterogeneous Aa 100/600 = 0.16
Homogeneous aa 150/600 = 0.25
Let me know if you have any other questions or if you need help explaining this problem.

Alexander W.
Also, to answer the second part of the question- HW assumes that when there is no selection, migration (gene flow), and no mutations, and we have random mating, then allele frequencies should stay the same from one generation to the next and it would be equilibrium .09/21/20