Mamata G. answered • 08/27/20

Experienced and dedicated Math tutor in any grade level..

26 Inch of steel cut into 3 peices..

Lets assume first piece is A

so second piece will be 2A as from the above condition,

so third piece will be 5A + 2 as its said 5 times of the first piece ( 5A ) and 2 inch more ( 5A+ 2)

now we can put all 3 pices togetheras,

A + 2A + 5A+ 2 = 26

subtracting 2 from both sides,

A + 2A + 5A + 2 - 2 = 26 - 2 = 24

A + 2A + 5 A = 24

8A = 24

dividing both sides by 8 we get,

A = 24/ 8 = 3

First piece is** 3 inch **

2nd piece is 3* 2 = **6 inch **( twice is first piece )

3rd piece is 3* 5 + 2 = **17 inc**h ( as from the condition ,5A + 2 )