(2, 3) can be written as f(2) = 3
In y=2f(3x-1)+5, if x=1 then f(3x-1) = f(2).
3x-1 = 2
3x = 3
x=1
So let's plug in x=1 to the transformed function:
y=2f(3*1-1)+5
y=2f(2)+5
since f(2) = 3, then
y=2(3)+5
y = 11
Therefore the point we are looking for is (1,11).