How do I solve the following prealgebra question: 8x+16=24

Answer 1

Solving the equation in this case refers to finding a value for x. Usually that is written as x = 3 for example. Here the end result is to have just the x on one side of the equation and a real number on the other.

Given: 8x +16 = 24

Step 1: Subtract 16 from both sides of the equation.

8x +16 -16 = 24 - 16

8x +0 = 8

8x = 8

Step 2: Divide both sides by 8

8x/8 = 8/8

x = 1

So you get x = 1 as your final answer.

Answer 2

Remember you have to do the inverse operation to both sides 8x+16-16=24-16

8x=8

then you divide both sides by 8

8x/8=8/8

x=1

Then, you can check to make sure the solution works by substituting it back in the equation.

8 times 1+16=24. Yes, the solution works.

Answer 3

8x + 16 = 24

You want x by itself on one side of the equation. Subtract 16 from both sides.

8x + 16 - 16 = 24 - 16

8x = 8

Divide by 8 on both sides.

8x/8 = 8/8

x = 1