Find an Online Tutor Now

Jonathan Z.

asked • 05/27/20

How do you solve for y in terms of x in this logarithmic equation?

log x + 2 log y = 3 log 2


Answers are given as y = 2 x sqrt(2/x) / -2 x sqrt(2/x) (rejected) or y = sqrt(8/x) / y=-sqrt(8/x) (rejeted)


I got 10^[log10(8/x)]/2, how do I solve for y in a manner that will get me one of the answers above?

1 Expert Answer

By:

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.