
Arturo O. answered 05/27/20
Experienced Physics Teacher for Physics Tutoring
log(x) + 2 log(y) = 3 log2
2 log(y) = 3 log2 - log(x)
log(y2) = log(23) - log(x)
log(y2) = log(23/x) = log(8/x)
Take 10() of both sides.
y2 = 8/x
y = √(8/x) = 2√(2/x)
Jonathan Z.
asked 05/27/20log x + 2 log y = 3 log 2
Answers are given as y = 2 x sqrt(2/x) / -2 x sqrt(2/x) (rejected) or y = sqrt(8/x) / y=-sqrt(8/x) (rejeted)
I got 10^[log10(8/x)]/2, how do I solve for y in a manner that will get me one of the answers above?
Arturo O. answered 05/27/20
Experienced Physics Teacher for Physics Tutoring
log(x) + 2 log(y) = 3 log2
2 log(y) = 3 log2 - log(x)
log(y2) = log(23) - log(x)
log(y2) = log(23/x) = log(8/x)
Take 10() of both sides.
y2 = 8/x
y = √(8/x) = 2√(2/x)
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