What is an equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15x+3y=15?

Question

What is an equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15?

Answer 1

Use the point and the form of the equation given.

x+3y = 6 + 3(1)

x + 3y = 9

Answer 2

Parallel lines have equal slopes, so the slope of the parallel line is

m = -1/3

y = (-1/3)x + b

Find b from the given point.

1 = (-1/3)(6) + b

1 = -2 + b

b = 3

y = (-1/3)x + 3