Please help me asap

Question

Given the following graph, write the intercept form of the function. Then transform it into the standard and vertex forms.

Answer 1

Since the x intercepts are -1 and 3, I would use those to get the factors.

y=a(x+1)(x-3)

To find a, pick a point on the parabola and plug in the values. I used the point (2,-6)

-6=a(2+1)(2-3)

-6=a(3)(-1)

-6=-3a

a=2

Put that into the equation

y=2(x+1)(x-3)

To put it in standard form, FOIL out the binomials

y=2(x²-3x+x-3)

y=2(x²-2x-3) Distribute the 2

y=2x²-4x-6