J.R. S. answered • 05/19/20

Ph.D. in Biochemistry--University Professor--Chemistry Tutor

Total final volume = 25.0 ml + 40.0 ml = 65.0 ml

Final [AlBr_{3}]: (25.0 ml)(0.50 M) = (65.0 ml)(x M) and x = 0.192 M AlBr_{3}

Final [NaBr]: (40.0 ml)(0.35 M) = (65.0 ml)(x M) and x = 0.215 M NaBr

AlBr_{3} ==> Al^{3+} + 3Br^{-}

NaBr ==> Na^{+} + Br^{-}

[Br^{-}] from AlBr_{3} = 0.192 M x 3 = 0.576 M Br^{-}

[Br^{-}] from NaBr = 0.215 M x 1 = 0.215 M Br^{-}

Total [Br^{-}] = 0.576 M + 0.215 M = 0.791 M = 0.79 M (2 significant figures)

Stephanie B.

Then, how many total moles of Br- in how many total L of solution?05/19/20