HOA P. answered 05/13/20
Excellent, hardworking and passionate Math Tutor
(g*f)(x) = g(f(x))= g (x + 3) Since f(x) = x+3
We have g(x) = x2 - 4
g(x+3) = (x+3)2 - 4 = x2 +6x +9 -4 = x2 +6x +5 =(x+5) (x+1)
So (g*f) (x) =(x+5) (x+1)
Tim D.
asked 05/13/20Given f(x) = x + 3 and g(x) = x^2 – 4 Find (𝑔 ∘ 𝑓)(𝑥)
HOA P. answered 05/13/20
Excellent, hardworking and passionate Math Tutor
(g*f)(x) = g(f(x))= g (x + 3) Since f(x) = x+3
We have g(x) = x2 - 4
g(x+3) = (x+3)2 - 4 = x2 +6x +9 -4 = x2 +6x +5 =(x+5) (x+1)
So (g*f) (x) =(x+5) (x+1)
Erick G. answered 05/13/20
Mechanical Engineer specializing in STEM
g of f of x would be
=(X+3)^2-4
=(x+3)(x+3)-4
=(x^2+6x+9) - 4
=x^2+6x+5
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