If the dimensions of a block of wood are length = 7 m, width = 17 cm, and height = 999 mm, can you find the buoyant force on the block when the density is 507 kg/m^3 ?

Answer 1

Convert dimensions into meters:

length = l = 7 m

width = w = 17cm * 10^-2 meter/cm = 0.17 m

height = h = 999 mm * 10^-3 m/mm = 0.999 m

l * w * h = V = 1.18881 m^3 = Volume

density = ρ_w = 507 kg/m^3

gravity = 9.80665

Buoyant Force= F_A =ρ_w * V * gravity

F_A = 5910.73 Newtons