Inactive Tutor answered 05/05/20
The answer to this question is 13,15, which are the two consecutive positive odd integers that answer this question. We can obtain this answer using the following method:
Start by assigning the variable x to the larger number, which leaves the expression x-2 to represent the smaller number (as odd numbers are 2 apart)
x2 - (x-2)2 = 56
x2 - (x2 -4x + 4) = 56 >Expanded using polynomial multiplication (x-2)*(x-2)
x2 - x2 +4x - 4 = 56
4x - 4 = 56
4x - 4 + 4 = 56 + 4 > Using the additive property of equality
4x = 60
4x/4 = 60/4 > Using the division property of equality
x = 15
Therefore, we get a value of 15 for x, or the larger number, so x-2=13, the smaller number, giving us an answer of 13 and 15 as the two consecutive positive odd integers that have a difference of 56 between their squares.