J.R. S. answered 04/29/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
For a 1st order reaction, the integrated rate law is [A] = [Ao]e-kt
We can solve for k and then for 1st order reaction, t1/2 = 0.693/k so we can find t1/2
[A] = 0.15 M
[Ao] = 1.22 M
t = 18 sec
Solve for k
0.15 = 1.22e-18k
ln 0.15 = -18k ln 1.22
-1.897 - 0.1989 = -18k
-2.0959 = -18k
k = 0.1164
Now solve for t1/2
t1/2 = -.693/k = 0.693/0.1164
t1/2= 5.95 = 6 sec