Math problem finding length and perimeter prealgebra

Question

Find the length of a rectangular lot with a perimeter of 76 meters if the length is 6 meters more than the width

Answer 1

Perimeter = 2 * length + 2 * width = 76

We are given that length is 6 meters more than width, so we can express length as width + 6

Substituting into the above equation for perimeter:

Perimeter = 2 * (width + 6) + 2 * width = 76

Expanding: 2 * width + 12 + 2 * width = 76

4 * width + 12 = 76

4 * width = 64

width = 16

length = width + 6 = 22 meters