Graph -3x-y=-3 and tell wether it’s a function

Answer 1

Easiest way is to graph the line with either slope-intercept from of y=mx+b where m is the slope and y is the y-intercept.

-3x - y = -3

a) Rearrange the original equation so y is by itself of the left side, by adding 3x to both sides, we get:

-3x + (3x) - y = -3 + 3x which simplifies to -y = -3 + 3x, then ...

b) by dividing both sides by -1, we get y = 3 - 3x, which is written as y = -3x + 3

c) Graphy graph a line with a slope of -3 and y-intercept of 3

d) pick the point of (0, 3) and then plot points at slope of -3 (up 3, left 1, up 3, left 1, up 3, left 1)

e) You will get a diagonal line (like the backslash symbol \

f) Once you have your line, draw a vertical line anywhere on the graphed line, and if the vertical line only crosses in one place (which it does) - then you have a function

THUS: this is a function!

Answer 2

-3x - y = -3

-y = 3x - 3

y = -3x + 3

So, we have a y-intercept of 3 and a slope of -3/1. Put a dot at (0,3), then go down 3 and right one for your next point. Comtinue.

Remember also that -3/1 = 3/-1, so you can go up 3 and left 1.

Now, if we draw a vertical line through our graph at sny point, does it cross twice? You tell me!