How do I find the length of both legs of a right triangle with only the hypothenus?

Question

I really need help with this. The hypothenus is 25 and I have nothing else.

Answer 1

a²+b²=c² is the equation. c is the hypotenuse. Plug in the values.

a²+7²=25²

a²+49=625 Subtract 49 from both sides of the equation

a²+49-49=625-49

a²=576 Take the square root of both sides

√576=a

a=24

Answer 2

They could be most anything, as long as the sum of the squares of the two sides = 25

There is a familiar 5-4-3 right triangle where 5 squared = sum of 4 squared plus 3 squared.

So maybe you're dealing with that triangle with a multiple of 5 or

25-20-15. The other two sides may be 20 and 15, if this is what you're dealing with. It's the simplest solution.

5x5 by 5x4 by 5x3 = 25 by 20 by 15 right triangle.

But apparently there is more information, possibly that one side is 7?

Then it's a 25-24-7 triangle.