J.R. S. answered 03/31/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
1). It is assumed that the question is asking for the number of moles of oxygen?
PV = nRT and if we assume we have 1 liter, then we have...
(1.11 atm)(1 L) = n(0.0821 Latm/Kmol)(311K)
n = (1.11)/(0.0821)(311)
n = 0.0435 moles
2). Since we are given the mass, and asked to find the molecular weight, we need to find moles.
Assume we have 1 liter of the gas, and use the ideal gas law...
PV = nRT
n = PV/RT = (1.06 atm)(1 L)/(0.0821 Latm/Kmol)(317K)
n = 0.0407 moles
molecular weight = 2.41 g/0.0407 moles = 59.2 g/mole