Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.

Question

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 is a leap year.

Ex: If the input is:

1913

the output is:

1913 is not a leap year.

Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.

bool IsLeapYear(int userYear)

#include <iostream>

using namespace std;

/* Define your function here */

int main() {

/* Type your code here. Your code must call the function. */

return 0;

}

Answer 1

using namespace std;

#include <iostream>

bool IsLeapYear( int year)

{

bool boolReturn=false;

if ( (year % 100)==0)

{

if ((year % 400)==0)

{

boolReturn=true;

}

}

else

{

if ( (year % 4)==0)

{

boolReturn=true;

}

}

return(boolReturn);

}

int main()

{

int year;

bool boolReturn;

cout << "PLEASE INPUT THE YEAR :>";

cin >> year;

boolReturn = IsLeapYear(year);

if (boolReturn)

{

cout << year << " is a leap year " << endl;

}

else

{

cout << year << " is NOT a leap year " << endl;

}

}