If all of the dimensions of the aquarium were doubled , what would be the volume of the new aquarium ?

Question

L=6 in W=10 in H=9 in

Answer 1

The volume of the aquarium would be doubled. So L would be 12. Width would be 20 and Height would be 18. The problem would look like this

12x20x18=4,320

Answer 2

Volume is solved with the equation LxWxH. You can solve this problem by doubling each original measure then putting them in the equation. So, a length of 6in becomes 12in, a width of 10in becomes 20in, a height of 9in becomes 18in. The equation is now 12x20x18. 12x20= 240. 240x18= 4,320. This means the new aquarium has a volume of 4,320in³.

Answer 3

Volume= L* W * H

so if you double all the dimensions =>

volume = 2L * 2W * 2H