
Nestor R. answered 02/25/20
Mathematically-oriented professional with many years of experience
Let T = cost per credit hour and Y = year.
When Y = 1990 T = $93
When Y = 1999 T = $210
Since the change is assumed to be linear, the slope is ($210 - $93) / (1999 - 1990) = $117/9 = $13/year
T = $93 + $13*(Y-1990)
When Y = 2003, T = $93 + $13(2003-1990) = $262
Recall the change T is assumed to be linear over Y.
In 1999, T was given as $210. The slope, m = $13/year.
$310 - $210 = $91. Since m = $13/year, $91/$13 = 7 years have passed since 1999.
When T = $301, Y = 2006.
As a check, notice that in 2003 T was found to be $262, and 301-262 = 39 and 39/13 = 3 more years. 2003 + 3 = 2006