Samiha A.
asked • 02/24/20100 cell phone batteries were tested for danger of overheating. 12 of those tested batteries were found to be defective. Two batteries are being randomly selected without replacement. Find the probability of randomly selecting 2 defective batteries.
Matthew S. answered • 02/24/20
Ph in Operations Research with extensive background in probability
Prob(both batteries defective) = Prob(1st battery selected is defective) x Prob(2nd battery selected is defective | 1st battery selected is defective)
= (12/100)x(11/99)
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