A ball rolls down a hill with a height of 10m and the ball has a mass of 20kg. and then bounces up 4 m and has a gravity of 10. what is it's dissipated energy

Answer 1

At the bottom of the hill, its energy was mgh₁, where h₁ is the height of the hill. But if it bounces up to a height h₂ with h₂ < h₁, it ends up with a lower energy of mgh₂. The dissipated energy must be the absolute value of the change in energy ΔE.

|ΔE| = |mgh₂ - mgh₁| = mg(h₁ - h₂)

Plug in these numbers and finish from here:

m = 20 kg

g = 9.8 m/s²

h₁ = 10 m

h₂ = 4 m