find the ordered pair

Question

can anyone explain how to determine ordered pairs from an x y equation such as y=4x+2

Answer 1

What you need to do is place a value into the input (x-variable), and solve to get your output (y-variable)

So, for example, place 0 for x:

y = 4 * 0 + 2

y = 0 + 2

y = 2

So one ordered pair would be (0, 2).

If you have a value for y, you can use that to find x. Say you have 10 for the value of y:

10 = 4x + 2

Subtract 2:

8 = 4x

Divide by 4:

2 = x

So another ordered pair would be (2, 10). Remember, the x-value always comes before the y-value.

Answer 2

When the equation is in Y = mX + b form, you start with the b or Y-intercept. That's where the line crosses the Y-axis. At that point, X is zero so your first ordered pair is (0,2). From that point you use the m or slope to find others. The 4 can be regarded as 4/1, with 4 the units up or down and 1 the units left or right. Since 4x is positive, we'll go right. So at point (0,2) go up 4 units and right 1. That's your next X,Y pair (1,6). Keep going. Up 4 right 1 puts you at (2,10).