Denise G. answered 01/22/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The first step you can do is factor out the GCF, which is x. The result is:
x(x4 - 4x3 - 2x2 + 4x + 1) This gives the first zero, x=0
Now, we can use synthetic division. Possible factors would be 1 or -1, we can try both of those.
1 | 1 -4 -2 4 1
1 -3 -5 -1
1 -2 -5 -1 0 The zero in the last position means a remainder of 0, which confirms the zero x=1
We can use synthetic division again with the result as the next step and try x=-1
-1 | 1 -2 -5 -1
-1 4 1
1 -4 -1 0 Once again, zero as the remainder confirms that we have another zero, x=-1
The polynomial that remains is x2-4x-1 This can be solved using the quadratic formula.
a=1 b=-4 c=-1
[-(-4)±√(-4)2-5(1)(-4)]/[2(1)] Simplify
[4±√20]/2 Simplify
4/2±2√5/2 Simplify
2±√5
In summary, the 5 solutions are:
x=0,1,-1,2±√5