A car of mass 3000kg travels at a constant velocity of 5.0m/S. Calculate the time it would take a force of 4500N to accelerate the car to a velocity of 30.0m/s.

Question

Can I please have the equations that would be used to calculate as well?:)

Answer 1

Equations:

F=ma

v=v₀+at

Using the given values:

F=4500 nt

m=3000 kg

v=30 m/s

v₀=5 m/s

Solving for a=F/m=4500/3000=1.5 m/s²

then t=(v-v₀)/a=(30-5)/1.5=16 2/3 s

Jim

Answer 2

This is how to solve to the problem step by step:

1) always define your variables: velocity _initial (v_i) = 5 m/s, velocity _final (v _f) = 30 m/s, Force = acceleration×mass => acceleration(a) = Force / mass = 1.5 ms ², time(t)= ?

2) the goal now is to find the displacement, the change, in velocity which is known a Δv or Δvelocity by subtracting the initial velocity from the final velocity, Δv = v _f -v _i = 30 m/s - 5 m/s = 25 m/s

3) finally to solve for t divide Δv by the acceleration you solved for earlier to get you answer of approx. 16.667 seconds