equation of line t is
y + 8 = 1 2 ( x + 8 ) I will make the equation in slope-intercept form by eliminating 8 from the left side
y = 12(x+8) - 8
y = 12x + 96 - 8
y = 12x + 88
The slope/gradient (m) of line t is 12
line u is perpendicular with line t which means that
slope line t * slope line u = -1
12 * slope line u = -1
slope line u = - 1/12
line u pass through (1, -7)
y = mx + c put the slope of line u and the coordinate into the line equation
-7 = -1/12 (1) + c
-7 + 1/12 = c
-83/12 = c
equation of line u is
y = -1/12x -83/12
