
Lindsay B. answered 12/03/19
Statistics tutor for people who think they hate statistics!
Knowns:
- Mean (µ=11.5)
- Std, Dev (σ=2.7)
c.) P(10 ≤ x ≤14)
- Break into two pieces:
- P(10 > x ) -> Standardize
- P(10-11.5)/2.7 = z > (-1.5)/2.7= -0.56
- Look at z-table (http://www.z-table.com/): P( z> -0.56) = 1-0.2877=0.7123
- P(x < 14) -> Standardize
- P(11.5-14)/2.7 = (-2.5)/2.7 = -0.93
- Look at z-table (http://www.z-table.com/): P(z < -0.93) = 0.1762
- Remember that a normal distribution is symmetrical. Thus:
- 0.7123 - 0.1762 = 0.536
- Therefore the probability of a male baby being between 10 and 14 pounds is 53.6%.
d.) You have to define "unusual" first. p < 0.05 is a standard metric so we will use that.
- P(x>17) = (17-11.5)/2.7 = (6)/2.7 = 2.22
- Look at the table (http://www.z-table.com/) which gives the probability a baby weighs less than 17 lbs which is 0.9868. Thus, the probability that P(z>2.22) = 1 - 0.9868= 0.0132
- Since 0.0132 is less than 0.05, it would be unusual at the 5% significance level that a male baby would weigh at least 17 lbs or more. Since 0.0132 < 0.05.