A coffee cup has a heat capacity of 62.6J∘C. If the coffee cup's temperature increases by 1.20∘C, how much heat has it absorbed?

Question

Round your answer to the nearest tenth.

Answer 1

q = Ccal x ΔT

q = 62.6 J/deg x 1.20 deg = 75.12 J = 75.1 J (rounded to a tenth)