Mark M. answered 11/19/19
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = √(25 - x2)
[f(x+h) - f(x)] / h = [√(25 - (x+h)2) - √(25 - x2)] / h
Multiply and divide by √(25 - (x+h)2) + √(25 - x2) to obtain:
[(25 - (x+h)2 - (25 - x2)] / [h(√(25 - (x+h)2) + √(25 - x2))]
= [x2 - x2 - 2xh - h2] /[ h(√(25 - (x+h)2) + √(25 - x2))]
= h(-2x - h) / [h(√(25 - (x+h)2) + √(25 - x2))]
= (-2x - h) / [√(25 - (x+h)2) + √(25 - x2)]
Replace h by 0 to get -2x / [2√(25 - x2)] = -x / √(25 - x2)