
Michael H. answered 10/16/19
High School Math, Physics, Computer Science & SAT/GRE/AP/PRAXIS Prep
Let An be the account balance at the end of the nth month. Let
A0 = the original balance, in this case $4500,
i = the monthly interest rate charge on the outstanding debt, in this case, i = 27% / 12,
p = the minimum percent of the current balance to be paid each month, in this case, 3%.
To get to balance at the end of month n+1, we form this equation:
An+1 = An + i*An - p*An
This can be simplified to:
An+1 = An * (1 + i - p)
Looked at another way,
An+1 / An = 1 + i - p
Remember that n is arbitrary; it represents 1, 2, 3, etc. So all we have to do to get the balance after the first payment is multiply the original balance by 1 + i - p. To get the balance after the second monthly payment, we multiply the first month's balance by the same number, 1 + i - p.
To get the balance after 32 months, we form this product of 32 fractions:
(A32 / A31) * (A31 / A30) * (A30 / A29) * • • • * (A1 / A0)
We will simplify this product two different ways.
First, we substitute each fraction with (1 + i - p) to get
(1 + i - p) * (1 + i - p) * (1 + i - p) * • • • * (1 + i - p)
Since there 32 such terms, we get the product:
(1 + i - p)32
The second way is to note that
(A32 / A31) * (A31 / A30) * (A30 / A29) * • • • * (A1 / A0)
can be simplified to just
A32 / A0
These two simplifications must be equal, so we conclude that
A32 / A0 = (1 + i - p)32, or
A32 = A0 * (1 + i - p)32
Now we substitute in the given values as follows:
A32 = (4500) * (1 + 0.27/12 - .03)32 = 4500 * 0.992532 = 4500 * 0.78591666 = 3536.62