Melvin began a plan for this proof. Since segment AB ≅ segment CD, then AB = CD. He knows that BC = BC, by the reflexive property of equality. What is a possible next step in Melvin’s proof?

Question

Answer choice

A. Use the segment addition postulate to show that AC = AB + BC and BD = BC + CD.

B.Substitute AB for CD.

C.Measure segment AC and segment BD to prove that they are the same length.

D.Use the transitive property of equality to show that AC and BD are equal because they are equal to the same expression.

Answer 1

This appears to have some missing information. Was there a diagram or another portion of the question?

With only what you have given us the answer is unclear. If we make some assumptions we can attempt this anyway.

I think that the beginning of this question sets up the story of Melvin taking a geometry test. The question asks melvin to formulate a proof that shows AC = BD

Multiple choice questions often give hints as to the answer by what choices they present.

It seems that answer A would be one step on the path to answer D. Therefore D is not the next step.

Answer C is not something that would be in a proof because a proof requires previous postulates being accepted. Therefore measuring it is not going to be part of the proof.

That leaves A and B. A seems to be setting up for B.

I think that a,b, and d are all steps in this proof.

They seem to go in this order.

A leads to b which leads to D There for AC = BD