The graph of y = Ax2 + Bx + C where A < 0 is a parabola opening downward. The maximum value of y occurs at the vertex, which has x-coordinate -B / (2A).
So, for h(x) = -4x2 - 2x + 8, the maximum occurs when x = -(-2) / [2(-4)] = -1/4
Maximum value of h is h(-1/4) = -1/4 + 1/2 + 8 = 8.25
Zorg S.
Thanks sooooo much, Mark M.!!!!!!09/28/19