J.R. S. answered 09/13/19
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Clausius-Clapeyron equation:
ln(P2/P1) = ∆Hvap/R (1/T1 - 1/T2)
P1 = 1 bar
P2 = ?
T1 = 56.1 + 273 = 329.1K
T2 = 43.5 + 273 = 316.5K
∆Hvap = 29.1 kJ/mole = 29,100 J/mole
R = 8.314 J/mol-K
ln(P2/1) = 29,100/8.314 (1/329.1 - 1/316.5)
ln P2 = 3500 (0.003039 - 0.003160)
ln P2 = 10.6 - 11.06 = -0.46
P2 = 0.63 bar