1.5 L has two significant figures, not one. So when you change to cm^3, it will be written as 15×10^2 cubic cms. And when you determine mass, it will be

15×10^2 ×19.3 = 289.5 × 10^2 = 2.9×10^5 grams

Hyunjin H.

asked • 09/09/19A gold statue has a volume of about 1.5L. How many cm^3 is this

my answer: 1,500cm^3 = rounded to 1 significant figure is (2,000cm^3)

apparently its wrong but I don’t know how^^^

This then leads to the following.....based on the last two questions, what is the mass of the gold statue?

Density=19.3 (I did get that right)

M=DxV

so I did 19.3(2000) = 38,600 g/cm^6 which rounded to the significant figure is (40,000g/cm^6)

which is also wrong^^^

Am I wrong? Am I rounding to the wrong figure?

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1.5 L has two significant figures, not one. So when you change to cm^3, it will be written as 15×10^2 cubic cms. And when you determine mass, it will be

15×10^2 ×19.3 = 289.5 × 10^2 = 2.9×10^5 grams

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