Joshua G. answered 08/22/19
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Since sin θ = a/3 and sin θ = length of the side opposite of θ/ length of the hypotenuse, we have that
length of the side adjacent to \theta = \sqrt{3^{2} - a^{2}}
= \sqrt{9 - a^{2}}
Using the preceding information and the definitions of cos θ, tan θ, cot θ, csc θ, and sec θ we have the following:
cos \theta = length of the side adjacent to \theta/length of the hypotenuse
= \sqrt{9 - a^{2}}/3
tan \theta = length of the side opposite of \theta/length of the side adjacent to \theta
= a/\sqrt{9 - a^{2}}
cot \theta = 1/tan \theta
= 1/[a/\sqrt{9 - a^{2}}]
= \sqrt{9 - a^{2}}/a
csc \theta = 1/sin \theta
= 1/[a/3]
= 3/a
sec \theta = 1/cos \theta
= 1/[\sqrt{9 - a^{2}}/3]
= 3/\sqrt{9 - a^{2}}