HELP! Assuming the pendulum is on the Earth and g = 10m/s2, what is the period if the length is 10 m?

Question

1. A. 2π s
2.  B. 1 s
3.  C. π s
4.  D. π/2 s

Answer 1

assuming a simple pendulum ("small" swing), the period is given by:

T = 2π √(L/g)

where T is the period, L length of pendulum (assuming mass concentrated at end), g is gravity

= 2π √[10(m)/10(m/s²)] = 2π seconds is the period, T. A. is the answer