A 615 mL gas sample at STP is compressed to a volume of 223 mL, and the temperature is increased to 21◦C. What is the new pressure of the gas in Pa? Answer in units of Pa

Answer 1

Assuming a perfect gas P₁V₁/T₁ = P₂V₂/T₂

P2 is unknown

P₁ = 10⁵ Pa

V₁ = 615

V₂ = 223

T₁ = 273.15 K

T₂ = 294.15

Then (10⁵)(615)(/273.15) = (P₂)(223)/(294.15) or P₂ = 296,987.3 Pa