
Kai V. answered 08/12/20
First Year Molecular Medicine Ph.D Student
Hey there,
You're on the right track! This is a concentration problem, so you'll want to use C1V1=C2V2
For the first step, you're absolutely right--you just take the total ml (30 ml) and multiply that by the concentration you want of your solute (20mg/ml).
(ml solvent) * (final concentration) = (mass solute)
30 ml H2O * 20mg/ml = 600 mg of your solute needed, so congo red or coomassie.
For part 2, you'll want to set up two equations: one for the coomassie, and one for the congo red.
You have the final concentration that you want, as well as the final volume you want, so you can plug that in to C2V2
For coomassie, that looks like (20 micrograms/ml * 500ml) and for congo red, that looks like (40 micrograms/ml * 500ml). After doing those equations, you'll have a concentration in micrograms (μg) that you'll need to convert to mg to get the correct measurement.
For coomassie, that looks like (20μg/ml *500ml) = 10,000μg needed in 500ml, which you can then convert to mg through dividing by 1000 (mg is 1000 times μg), which gives you 10mg.
That means you'll need 10mg total of coomassie added to 500ml of sterile water to make a concentration of 20μg/ml.
So, now that we have the far side of C1V1=C2V2, we just need to do some algebra and isolate V1, as that is the volume of our stock solution from the first part that we'll need to add.
C1V1=C2V2 becomes C1V1=10mg
C1 we know from our stock solution of coomassie: C1 = 20mg/ml
So, C1V1=C2V2 becomes (20mg/ml) * V1 = 10mg
And then by dividing the whole equation by C1 (20mg/ml), we get V1 = (10mg)/(20mg/ml) = .5ml of stock to add to 500ml of sterile water to get a coomassie concentration of 20μg/ml.
You can do the same overall process to figure out the amount of Congo Red stock solution you'll need to add.
If you get tripped up in the process, here's a cheat sheet for the steps:
1) Determine C2V2 by taking the final concentration and multiplying by the final volume you want
2) Take your initial concentration, C1, and divide C2V2 by your initial concentration--this will leave you with V1 on one side of the equation.
3) Add V1 of your stock solution to V2 of your sterile water, and you have the concentration you want!
Hope that helps you or others (I have the distinct feeling you may have figured this out by now, given that this question was asked quite some time ago).
Best,
Kai