Given f (x)=x^2+4x-5 find:

Question

a. Vertex

b. Axis of symmetry

c. Max or Min.

d. Range

e. Interval increasing

f. Interval decreasing 

Answer 1

f(x) = x^2 + 4x -5 = (x+5)(x-1) x intercepts are 1 and -5, y intercept =-5

f(x) = x^2 +4x -5 = (x^2 +4x +4) -5 -4 = (x+2)^2 -9, vertex = (-2,-9) = minimum point. axis of symmetry is x=-2

range is -9 to infinity

It's an upward opening parabola graphically. decreasing for x less than -2

increasing for x>-2