A father tells his son "3 years ago I was 13 times your age, and in 3 years I will be 4 times your age" What is their age now

Answer 1

Father is 29 years old. Son is 5 years old.

3 years ago Father was 26, and son was 2. 26=13 x 2

In 3 years, Father will be 32 and son will be 8. 32 = 4 x 8

Set up the problem with 2 equations

Let F = father's age now, and S= son's age now

Then F-3 = 13(S-3) and F+3= 4(S+3)

Simplify, subtract one equation from the other and solve for one age, then

substitute to get the other age.

Or plot the 2 equations on a graph and see where they intersection.

The intersection point will have the F and S coordinates of their current ages.