I don't know how to solve this. So an answer and an explanation would be great

Question

Diane averages 6 mph walking to school. Averaging 35 mph on the way back home by car, she takes 3/4 hour less time. How far is the school from her home?

Answer 1

I used the distance speed time formula to solve. (D = S * T)

D = distance (to school)

S = speed

T = time (to walk to school)

First I solved for T:

6T = 35 (T-.75) 6 MPH times how long it took to walk to school equals 35 MPH times how long it

took to walk to school minus .75 of an hour

6T = 35T - 26.25

29T = 26.25

T = about .9 or 54 minutes

Then I substituted in using the distance speed time formula:

D = 6 * .9

D = 5.4 miles

Answer 2

T=time going to school

T-(3/4)=time returning from school

Distance to and from is the same!

6T=35[T-(3/4)] => 116T=105

T is approx .905 hrs and 6T is approx 5.4 miles

I think this is correct, but I am always suspicious when the arithmetic look so messy!