Christy, your equation is y = (x-h)2 + k, where (h,k) is your vertex.
Since a "normal" parabola has its vertex at (0,0), we have y = a(x-0)2 + 0 = ax2
1. Remembering that h is your x coordinate, our new x coordinate is -10, because we went from 0 left 10 to -10.
Therefore, our equation is y = (x-(10))2 = (x + 10)2, so your answer is the last.
2. This does the opposite of what you would think. It stretches the graph horizontally by a factor of 3. If you had y = 3x2, it would shrink it horizontally by 1/3.
Hope this helps!