Johnathan N. answered • 05/17/19
Biologist, Chemist, Mathematician, Statistician, and Coder
Let's take it line-by-line:
Clara has 420 pieces of candy
Clara (420)
She gave 47% of the candy to Adam and the rest to Chloe
47% * 420 ∼ 197 and 53% * 420 ∼ 223
Clara (000), Adam(197), Chloe(223)
Chloe now has 371 pieces of candy because she bought more at the "Candy R Us" TM
Clara (000), Adam(197), Chloe(371)
But then, Chloe gave 18% of her candies to Michael
18% * 371 ∼ 67 and 82% * 371 ∼ 304
Clara (000), Adam(197), Chloe(304), Michael (067)
*Adam gave some of his candy to Bob. Bob already had 397 pieces of candy ...
Clara (000), Adam(197), Chloe(304), Michael (067), Bob (397)
and now he has 468 ...
468 - 397 = 71
197 - 71 = 126
Clara (000), Adam(126), Chloe(304), Michael (067), Bob (468)
that *Bob will eat*
Clara (000), Adam(126), Chloe(304), Michael (067), Bob (000)
Clara gave Bob all the candies that were given back by Chloe ...
Giving back the original 223 which is then handed to Bob
304 - 223 = 81
Clara (223), Adam(126), Chloe(081), Michael (067), Bob (000)
Clara (000), Adam(126), Chloe(081), Michael (067), Bob (223)
and Chloe gave 43% of her's as well to Bob
43% * 81 ∼ 35 and 57% *81 ∼ 46
35 + 223 = 258
Clara (000), Adam(126), Chloe(046), Michael (067), Bob (258)
Michael gave Bob 62% of his candies
62% * 67 ∼ 42 and 38% * 67 ∼ 25
42 + 258 = 300
Clara (000), Adam(126), Chloe(046), Michael (025), Bob (300)
After Bob ate 73% of his candies, what does he have now?
73% * 300 = 219 and 27% * 300 = 81
Clara (000), Adam(126), Chloe(046), Michael (025), Bob (081)
So Bob has 81 pieces of candy
