Having trouble with this problem can someone help me out

Question

Find the larger of 3 consecutive odd integers such that 5 times the first, decreased by the second exceeds twice the third by 16

Answer 1

Assuming n is an integer, then

Even numbers are 2n, and odd numbers are one above or one below, so an odd number can be represented as 2n+1.

So three consecutive odd integers a, b, and c would be

a=2n+1

b=2n+3

c=2n+5

The words translate to the math statement:

5a - b = 2c + 16

5(2n+1) - (2n+3) = 2(2n+5) +16

10n + 5 - 2n - 3 = 4n + 10 +16

8n + 2 = 4n + 26

4n + 2 = 26

4n = 24

n=6

So the three consecutive odd integers are 2(6)+1 = 13, 15,17 so the largest = 17.