solve the equation for exact solutions over the interval (0 degrees,360 degrees)

Question

3sinθ=sinθ-√3

Answer 1

The stated problem looks like 3sin(a) = sin(a) - 3^(1/2) if so, then 2sin(a) = -3^(1/2) = -1.732

or sin(a) = -.866 a = sin-1(-.866) a = -60 degrees= 300 degrees

but in the 3rd quadrant a = 240 degrees

sin(300) = sin(240) = -.866