Let R = rentals and P = price
The relationship between R and P is linear:
R = 108 - 6P
The income is PR = 108P - 6P2
The derivative of income with respect to price is 0 at P = 9, i.e. income will be maximized when P = 9
Sebastian S.
asked 04/12/19You run a canoe-rental business on a small river in Ontario. You currently charge $12 per canoe and average 36 rentals a day. An industry journal says that, for every fifty-cent increase in rental price, the average business can expect to lose two rentals a day. Use this information to attempt to maximize your income. What should you charge?
Let R = rentals and P = price
The relationship between R and P is linear:
R = 108 - 6P
The income is PR = 108P - 6P2
The derivative of income with respect to price is 0 at P = 9, i.e. income will be maximized when P = 9
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