Harold has $12.25 of change in quarters and nickels with five more nickels than quarters how many of each coin does he have

Answer 1

Let x = the number of quarters Harold has

Let x + 5 = the number of nickels Harold has

.25x + .05(x + 5) = 12.25

.25x + .05x + .25 = 12.25

.30x = 12.00

x = 40 quarters

x + 5 = 45 nickels