what is the slope and y- intercept of the line whose equation is 4x + y = - 4

Question

I have been struggling at graphing the last two weeks 

Answer 1

Kathy,

           Recall that the slope-intercept form of a straight line is y=mx+b, where m is the slope and b is the y intercept i.e. when x=0.

           If you solve the equation 4x+y=-4 for y we have y=-4x-4 now compare this equation with y=mx+b we find that m=-4 and b=-4 so the slope is -4 units of y per unit of x.

           The graph is a straight line that passes through the points (0,-4) and (-1,0) and slopes downward to the right.

 

Jim

Answer 2

The first thing you need to do is solve for y to put the equation in standard form.

 

Remember that standard form is y = mx+b.

Where m is the slope of the graph, and

b is the y-intercept.

 

All you have to do for this equation is subtract -4x from both sides of the equation to isolate y.

The equation is now:

 

y = -4 - 4x

 

If you prefer to rearrange the equation so that the x value is the leading term, simply do so like this:

 

y = -4x - 4

 

This puts the equation in standard form. Recall what each variable in the standard form equation means (listed above). The slope is the coefficient of x. 

 

The coefficient of x in this equation is -4. So, the slope of the line is -4.

 

The y-intercept is the constant term, or the number not multiplied by any variable (such as x). The constant term in this equation is -4. So, the y-intercept is -4.

Answer 3

convert equation to y = mx + b form where m is slope and b is y-intercept:

 

so we have,

 

4x + y = -4

 

y = -4x - 4

 

therefore m = -4 and b = -4