The sum of two numbers is 128. The first number is 18 more than the second number. What are the two numbers?

Answer 1

To find the two numbers, you will need to create a system of equations.

Let's say the first number is x and the second number is y.

"The sum of the two numbers is 128" can be converted into the equation x + y =128

"The first number is 18 more than the second number" can be converted into x = 18 + y

Remember, "is" usually means =

"more than" means addition

Now that you have two equations set up, you can solve the system using any of the methods that were taught in your class (graphing, substitution, and elimination). Please let me know if you would like additional help in solving the system.

Answer 2

1st put 18 for the 1st number

There is 128-18 = 110 left over. If we divide this evenly between the two numbers then the 1st number will be 18 more than the 2nd number.

110/2 = 55

So the 2nd number is 55 and the 1st number is 55+18=73.

Check:

73 + 55 =128 good

And 73-55=18 good

Answer 3

Hello, Tammy.

Okay, so we need to find 2 different numbers.

Let's call one of the numbers N.

Now, since the first number is 18 more than the 2nd number, we can call the 2nd number N - 18.

Now, we know that their sum is 128, so:

N + (N - 18) = 128

2N - 18 = 128

2N = 146

N = 73

So, now that we know that N = 73, we can find the 2nd number which is N - 18 = 55.

Therefore, the numbers are 73 and 55.