for an element which has two isotopes, the procedure follows
let us use Copper 63 and Copper 65
1. find the value of Cu from the Periodic Table, which, in this case, is 63.546
2. find the value of Cu63 = 62.9296
3. find the value of Cu65 = 64.9278
let x = abundance of Cu63; then the abundance of Cu65 will be 1 - x
4. our equation will be x(62.9596) + [(1-x)64.9278] = 63.546
then 62.9296x + 64.9278 - 64.9278x = 63.546
5. combining, 64.9278 - 63.546 = 64.9278x - 62.9296x
which yields 1.3318 = 1.9982x
6. solving for 1.3318/1.9982 = x
7. 0.6915 = x; then 1 - x = 0.308
8. multiplying by 100%, we get 69.15% and 30.8%