how many moles of CO2 are produced when 0.450 mol of C6H12O6 reacts in this fashion?

Question

how many moles of CO2 are produced when 0.450 mol of C6H12O6 reacts in this fashion?

Answer 1

the underlying chemical formula for this reaction is

C6​H12​O6​(s) + 6O2​(g) → 6CO2​(g) + 6H2​O(l), meaning that for every 1 mole of glucose that reacts, 6 moles of carbon dioxide are produced

so the calculation you want to do here is

0.450 mol C6H12O6 x (6 mol CO2 / 1 mol C6H12O6) = 2.7 mol CO2

so 2.7 moles of CO2 are produced

Answer 2

Kassandra - You need to post the formula of the reaction to answer the problem.  I'm going to guess that we're burning the hydrocarbon (many possible names, let's call it glucose) in oxygen like this:

 

C6H12O6 + 6O2 -> 6CO2 + 6H2O

 

 

Basically, every mole of C6H12O6  on the left uses up 6 moles of Oxygen and produces 6 moles of CO2 and 6 moles of H2O on the right.

 

6*0.45 = 2.7

 

So, 0.450 moles of glucose on the left react with 2.7 moles of Oxygen and becomes 2.7 moles of CO2 and 2.7 moles of water.